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A number is chosen at random from the number 10to99. By seeing the number a man will laugh if product of the digits is 12. If he choose three number with replacement then the probability that he will laugh at least once isA. `1-((3)/(5))^(3)`B. `(2(45^(2)+43^(2)-45xx43))/(45^(3)`C. `(98)/(125)`D. `1-((43)/(45))^(3)` |
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Answer» Correct Answer - D There can be four such numbers i.e 43,34,62,26. Whose product of digit is 12 implies Probability that the man will laugh by seeing the chosen numbers `=(4)/(90)=(2)/(45)` implies required probability `=1-(1-(2)/(45))^(3)=1-((43)/45)^(3)` |
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