A nurse measured the average heart beats of a patient and reported to the doctor in terms of time period as 0.8s. Express the heart beat of the patient in terms of number of beats measured per minute.

A nurse measured the average heart beats of a patient and reported to

1.	A nurse measured the average heart beats of a patient and reported to the doctor in terms of time period as 0.8s. Express the heart beat of the patient in terms of number of beats measured per minute.
Answer» Solution :LET the number of heart MEASURED be f. Since the time period is inversely proportional to the heart beat, then `f=(1)/(T)=(1)/(0.8)=1.25s^(-1)` One minute is 60 second, (1 second = `(1)/(60)` minute IMPLIES `1s^(-1)=60" min"^(-1)`) `f=1.25s^(-1)impliesf=1.25xx60" min"^(-1)=75` beats per minute.