A) One Covid 19 positive patient can infect an average of 1.7 persons if leftunquarantined.b) Success rate of keeping the patientsunder quarantined immediately withoutfurther infection be x%c) On 1st June, India had approximately 1Lakh active Covid 19 cases.Find the integer nearest to x so that theactive cases do not increase from the 1stJune level.

A) One Covid 19 positive patient can infect an average of 1.7 person

1.	A) One Covid 19 positive patient can infect an average of 1.7 persons if leftunquarantined.b) Success rate of keeping the patientsunder quarantined immediately withoutfurther infection be x%c) On 1st June, India had approximately 1Lakh active Covid 19 cases.Find the integer nearest to x so that theactive cases do not increase from the 1stJune level.
Answer» One Covid 19 positive patient can infect an average of 1.7 persons if left unquarantined.To find : the integer nearest to x so that the active cases do not increase from the 1st June level.Solution:there should be recovery RATE mentioned to find exact solution.but SEEING the options looks like user want solution as belowactive cases 1st june = 100000quarantined SUCCESSFULLY = x%= (x/100)100000 = 1000xunquarantined = 100000 - 1000X= (1000)(100 - x)infected per unquarantined = 1.7 personTotal infected = 1.7 × 1000(100-x)infected should be less than 100000=> 1.7 ×1000(100 - x) < 100000=> 1.7 (100 - x) < 100=> 170 - 1.7x < 100=> 1.7x > 70=> x > 70/1.7=> x> 41.17=> x = 42rate of keeping the patients under quarantined immediately withoutfurther infection be 42 %x = 42learn more:इस हॉस्पिटल मे 16 कोरोना के मरीज हे, 13 नंबर का ...brainly.in/question/17170505 One Covid 19 positive patient can infect an average of 1.7 persons brainly.in/question/18317010