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`A overset("Calcination")rarr CaO + MgO + underset("Colourless gas")((B))` When the colourless gas `(B)` is passed through lime water, initially a milky solution is obtained and on excess passage of gas `(B)` through the lime water, milkiness disappears. `(A)` is :A. `CaCO_(3)`B. `MgCO_(3)`C. `CaCO_(3).MgCO_(3)`D. `CaSO_(4).MgCO_(3)` |
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Answer» Correct Answer - C Since on calcination, i.e., heating the ore `(A)` is limited supply of `O_(2)`, both `CaO` and `MgO` are formed along with a colourless gas `(B). (A)` is `CaCO_(3).MgCO_(3).(A)` is known as dolomite. `CaCO_(3).MgCO_(3) overset("Calcination")rarr CaO + MgO + underset((B))(2CO_(2))` `CO_(2) + underset("Lime water")(Ca(OH)_(2))rarr underset("Milkiness") (CaCO_(3))+ H_(2) O` `CaCO_(3) +H_(2) O + CO_(2) rarr underset("Milkiness disappears") (Ca(HCO_(3))_(2))` On passing `CO_(2)` through lime water `[Ca(OH)_(2)]` solution, initially lime water turns milky due to formation of `CaCo_(3)`, which is insoluble in water. On excess passage of `CO_(2)` gas through lime water, milkiness disppears due to formation of `Ca(HCO_(3))_(2)`. Hence. (i) `A` is `CaSO_(3). MgCO_(3)`. |
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