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A p-n junction is fabricated from a semiconductor with band gap of `2.8eV`. Can it detect a wavelength of `6000nm`? |
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Answer» Energy, `E=(hc)/lambda=(6.6xx10^(-34)xx3xx10^(8))/(600xx10^(-9)xx1.6xx10^(-19))eV=2.06eVlt2.8eV` As `E lt E_(g)`, so p-n junction cannot detect the radiation of given wavelength. |
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