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A pair of dice is thrown. If the two numbers appearing are different , find the probability thet the sum of points exceeds 8. |
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Answer» SOLUTION :Let B be the event that sum of the POINTS exceeds 8. `THEREFORE` B={ (3,6),(4,5),(5,4),(6,3),(5,6),(6,5),(4,6),(6,4) } `therefore P (B) = absB/absS=8/30` |
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