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). A paper is in the form of a rectangle PQRS in whichPQ = 10 cm and QR = 7 cm. Two semi-circular portionswith QR and PS as diameters are cut off (As shown infigure 11.22). Find the area of the remaining part. |
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Answer» Area of remaining part = Area of rectangle-2 area of semicircle= lb-2πr^2/2= (10)(7) - 2((22/7) (3.5)^2/2)= 70-38.5= 31.5 cm^2 |
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