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InterviewSolution
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A parallel beam of light of 450 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1.5 m away. It is observed that the first minimum is at a distance of 3 mm from the centre of the screen. Calculate the width of the slit. |
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Answer» The distance of the nth minimum from the centre of the screen, `x_(n)=(n D lambda)/(a)` Where D - distance `lambda` - wave length a - width of the slit For first minimum, `n=1, 3 xx 10^(-3)=(1 xx (1.5)xx(450 xx 10^(-9)))/(a)a=(1 xx (1.5)xx(450 xx 10^(-9)))/(3 xx 10^(-3))a=0.225 mm`. |
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