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A parallel beam of monochromatic light is incident on a glass slab at an angle of incidence `60^(@)`. Find the ratio of width of the beam in the glass to that in the air if refractive index of glass is `3//2`. |
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Answer» Given `i=60^(@)`, `mu_(g)=(3)/(2)` Let, `d_(g)=`Width of beam in glass slab, and `d_(a)=` Width of beam in air We know that, `._(a)mu_(g)=(sini)/(sinr)` `(3)/(2)=(sin60^(@))/(sinr)` `impliessinr=(sqrt(3)xx2)/(2xx3)` `:.sinr=(1)/(sqrt(3))` `r=sin^(-1)(0.5773)` `=35.26^(@)` `(d_(s))/(d_(a))=(cosr)/(cosi)` `=(cos35.26^(@))/(cos60^(@))` `=(0.8164)/(0.5)=1.633` `(d_(s))/(d_(a))=(16)/(10)=(8)/(5)` `:.` Ratio of the width of beam `=8 : 5`. |
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