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InterviewSolution
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A parallel combination of three resistors takes a current of `7.5 A` from a `30 V` supply. If the two resistors are `10 Omega and 12 Omega`, find third one. |
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Answer» Correct Answer - `15 Omega` As `R = (V)/(I), R = (30 V)/(7.5 A) = 4 Omega` Let the third resistance be `x Omega`. Since `10 Omega, 12 Omega` or `x Omega` are in parallel, `(1)/( R)=(1)/(10)+(1)/(12)+(1)/(x)` or `(1)/(4)=(1)/(10)+(1)/(12)+(1)/(x)` or `(1)/(x)=(1)/(4)-(1)/(10)-(1)/(12)=(1)/(15)` or `x = 15 Omega`. |
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