1.

A parallel plate capacitor has area of each plate `A`, the separation between the plates is `d`. It is charged to a potential `V` and then disconnected from the battery. The amount of work done in the filling the capacitor Completely with a dielectric constant `k` is.A. `(1)/(2)(epsilon_(0)AV^(2))/(d)[1-(1)/(k^(2))]`B. `(1)/(2)(V^(2) epsilon_(0)A)/(kd)`C. `(1)/(2)(V^(2)epsilon_(0)A)/(k^(2)d)`D. `(1)/(2)(epsilon_(0)AV^(2))/(d)[1-(1)/(K)]`

Answer» Correct Answer - D
Work done = decrease in energy
ie `w-E_(1)-E_(2)=(1)/(2)(epsilon_(0)A)/(d)v^(2)-(epsilon_(0)Av^(2))/(2d)[1-(1)/(k)]`.


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