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A parallel plate capacitor has circular plates, each of radius 5.0 cm. It is being charged so that electric field in the gap between its plates rises steadily at the rate of 1012 V m-1s-1 .What is the displacement current? |
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Answer» Radius, r = 5cm = 5 x 10-2 m The rate okf electric frield, \(\frac{dE}{dt}\)= 1012 vm-1s-1 Displacement current, Id= ε0\(\frac{dφ_E}{dt}\) = ε0 \(\frac{d}{dt}\) (EA) = ε0(πr2) \(\frac{dE}{dt}\) = 8.85 x 10-12 x 3.14 x (5 x 10-2)2 x 1012 Id = 0.069 Id = 0.07 (or) 70 mA |
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