1.

A parallel plate capacitor has circular plates each of radius 6.0cm, It is charged such that the electric field in the gap between its plates rises constantly at the rate of `10^10V cm^-1s^-1`. What is the displacement current?

Answer» Here, `r=6xx10^-2m`,
`A=pixx(6xx10^-2)^2=36pixx10^-4m^2`
`(dE)/(dt)=10^10Vcm^-1s^-1=10^12vm^-1s^-1`
Displacement current,
`I_D=in_0(dphi_E)/(dt)=in_0A(dE)/(dt)`
`=(8.85xx10^-12)xx(36pixx10^-14)xx10^12`
`=01A`


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