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A parallel plate capacitor has its two plates connected to an ideal spring of force constant K. Relaxed length of spring is L and it is made of non conducting material. The area of each plate is A. The capacitor has a charge `q_(0)` on it. To discharge the capacitor through the resistance R, switch S is closed. If the time constant of the circuit is very large and discharge process is very slow, how much heat will be dissipated in the resistance? Assume that there is no friction and the plates always remains parallel to each other. |
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Answer» Correct Answer - `(q_(0)^(2)L)/(2 in_(0)A)-(q_(0)^(4))/(8 in_(0)^(2)A^(2)k)` |
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