Saved Bookmarks
| 1. |
A parallel-plate capacitor has plate area `A`, the distance between its two plates `x` and `y` is `d` and a dielectric slab of dielectric constant `epsilon_(r)` is filled between the regions. It is connected to a cell of emf `E`. If the dielectric slab is removed, then A. `(epsilon_(0)A)/(d)[epsilon_(r)-1]E` charge is absorbed by the cellB. `(epsilon_(0)A)/(d)[epsilon_(r)-1]E` charge flows through the circuitC. negative charge flows from plate `y` to plate `x`D. negative charge flows from plate `x` to plate `y` |
| Answer» Since battery is connected. potential difference remains constant. | |