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A parallel plate capacitor has plates with area A and separation d. A battery charges the plates to a potential difference `V_(0)`. The battery is then disconnected and a dielectric slab of thikness d is introduced. The ratio of the enrgy stored in the capacitor before and after the slab is introduced, isA. KB. `1/K`C. `A/(d^(2)K)`D. `(d^(2)K)/A` |
Answer» Correct Answer - A `EpropCandCpropk` `therefore" "Epropk` `E_(2)/E_(1)=k_(2)/k_(1)=k/k_(1)=k/1" "(thereforek_(2)=kandk_(1)=1)` |
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