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A parallel plate capacitor is charge to a potential difference of 50v. It is then discharged through a resistance for 2 sec and its potential drops by 10v. Calculate the fraction of energy stored in the capacitance A) 0.14B) 0.50C) 0.25D) 0.64 |
Answer» The correct answer is option (d) Explanation: Vi = 50 v = (40/50)2 = 16/25 = 0.64 |
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