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A parallel plate capacitor is charged and then the battery is disconnected. When the plates of the capacitor are brought closer, thenA. energy stored in the capacitor decreasesB. the potential differences between the plates decreasesC. the capacitance increasesD. the electric field between the plates decreases |
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Answer» Correct Answer - A::B::C If the battery is disconected, then `q=`constant `C=(epsilon_0A)/d or Cprop1/d` d is decreased. Hence, C will increase. `U=1/2q^2/c or U prop 1/C` C is increasing.Hence U will decrease. `V=q/C or Vprop1/C` `C` is increasing. Hence, `V` will decrease. |
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