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A parallel plate capacitor of plate area `0.2 m^2` and spacing `10^(-2)` is charged to `10^(3)V` and is then disconnected from the battery. Amount of work required to double the plate spacing isA. `8.85xx10^(-5)J`B. `17.7xx10^(-5)J`C. `4.42xx10^(-5)J`D. `26.55xx10^(-7)J` |
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Answer» Correct Answer - A |
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