InterviewSolution
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InterviewSolution
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A parallel plate capacitor of plate separation `2 mm` is connected in an electric circuit having source voltage `400 V`. If the plate area is `60 cm^(2)`, then the value of displacement current for `10^(-6) sec` will beA. `1.062 amp`B. `1.062xx10^(-2)amp`C. `1.062xx10^(-3)amp`D. `1.062xx10^(-4)amp` |
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Answer» Correct Answer - b `I_(D)=epsilon_(0)(dphi_(E))/(dt)=epsilon_(0)(EA)/(t)=epsilon_(0)((V)/(d)).(A)/(t)` `=(8.85xx10^(-12)xx400xx60xx10^(-4))/(10^(-3)xx10^(-6))=1.602xx10^(-2)amp` |
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