1.

A parallel plate capacitor with air inbetween the paltes has a capacitance of 8 pF. The separation between the plates is now reduced by half and the space between them is filled with a medium of dielectric constant 5. Calculate the new value of capacitance.

Answer» `C_(0) = (in_(0) A)/(d) = 8 pF`
`C = K. (in_(0) A)/(d//2) = 2 KC_(0)`
`= 2xx5xx8 pF`
= 80 pF


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