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A parallel plate condenser with oil (dielectric constant 2) between the plates has capacitance C. If oil is removed, the capacitance of capacitor becomesA. `sqrt(2C`B. 2CC. `(C)/(sqrt2)`D. `(C)/(2)` |
Answer» Correct Answer - D The capacitance of a parallel plate capacitor with dielectric (oil) between its plates is. `C=(Kepsilon_(0)d)/(d)" …(i)"` when dielectric (oil) is removed, so capacitance `C_(0)=(epsilon_(0)A)/(d)" …(ii)"` Comparing Eqs. (i) and (ii), we get `C=KC_(0)` `rArr" "C_(0)=(C)/(K)=(C)/(2)" "(because K=2)` |
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