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A paramagnetic sample shows a new magnetisation of 8 "Am"^(-1) when placed in and external magnetic field of 0.6 T at a temperature of 4 K. When the same sample is placed in an external magnetic field of 0.2 T at temperature of 16 K, the magnetisation will be |
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Answer» `(32)/(3) Am^(-1)` So magnetisation, `I prop (B)/( T)` `therefore I_(1) prop (B_1)/( T_1) and I_(2) prop (B_2)/( T_(2))` `therefore (I_2)/( I_1) = (B_2)/( B_1) xx (T_1)/( T_2) ` `I_1= 8 "Am"^(-1) , "Taking" B_(1) = 0.6 T, T_(1) = 4K` `B_(2) = 0.2 T , T_(2) = 16` K `(I_2)/( 8) = ((0.2)/( 0.6)) ((4)/(16))` `I_(2) = (8)/(12) = (2)/(3) "Am"^(-1)` |
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