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A paricle is projected at an anged `theta` from the horizontal with kinetic energy (T). What is the kinetic energy of the particle at the highest point ? |
Answer» At highest point, velocity of projectile K.E. of projectile at highest point `= 1/2 m (cos theta )^2 = (1/2 m u^2) cos^2 theta` ` = T cos^2 theta`. |
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