A park is in the form of a rectangle 120 m × 100 m. At the centre of

1.	A park is in the form of a rectangle 120 m × 100 m. At the centre of the park there is a circular lawn. The area of park excluding lawn is 8700 m2. Find the radius of the circular lawn.(use π = \(\frac{22}7\))
Answer» Total area of rectangular park = 120 ×100 = 12000 m² Area of park excluding circular lawn = 8700 m² So, Area of circular lawn = 1200 – 8700 = 3300 m² = πr² = 3300 r² = \(\frac{3300\times7}{22}\) = 1050 m r = 32.40 m Total area of the park = 120 x 100 = 12000 Area excluding the lawn = 12000 - πr^2 = 8700 (given) So, πr^2 = 3300 \(\frac{22r^2}{7}\) = 3300 r^2 = 1050 So, r = root 1050 Hope it helps Ask of any doubt

A park is in the form of a rectangle 120 m × 100 m. At the centre of the park there is a circular lawn. The area of park excluding lawn is 8700 m2. Find the radius of the circular lawn.(use π = \(\frac{22}7\))

Answer»

Total area of rectangular park = 120 ×100 = 12000 m²

Area of park excluding circular lawn = 8700 m²

So,

Area of circular lawn = 1200 – 8700 = 3300 m²

= πr² = 3300

r² = \(\frac{3300\times7}{22}\) = 1050 m

r = 32.40 m

Total area of the park = 120 x 100 = 12000

Area excluding the lawn = 12000 - πr^2 = 8700 (given)

So, πr^2 = 3300

\(\frac{22r^2}{7}\) = 3300

r^2 = 1050

So, r = root 1050

Hope it helps

Ask of any doubt