1.

A partcle is projected with a velocity of 10sqrt(2)m//s at an angle of 45^(@) with the horizontal. Find the interval between the moments when speed is sqrt(125)m//s.

Answer»

Solution :`(G = 10m//s^(2)), u_(n) = 10, u_(y)=0`
`v^(2)=v_(x)^(2)+v_(y)^(2)`
`125 = 100 + v_(x)^(2)`

`v_(y) = 5""Deltat = (2v_(y))/(g)=(2xx5)/(10)` = 1


Discussion

No Comment Found