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A partcle is projected with a velocity of 10sqrt(2)m//s at an angle of 45^(@) with the horizontal. Find the interval between the moments when speed is sqrt(125)m//s. |
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Answer» Solution :`(G = 10m//s^(2)), u_(n) = 10, u_(y)=0` `v^(2)=v_(x)^(2)+v_(y)^(2)` `125 = 100 + v_(x)^(2)` `v_(y) = 5""Deltat = (2v_(y))/(g)=(2xx5)/(10)` = 1 |
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