1.

A particel of charge ` 1 mu C & ` mass `1 mg` moving with a velocity of ` 4 m//s` is subjected to a unifrm electric field of magnitude ` 300 V m` for ` 10 sece`. Then it s final speed cannot be :A. ` 0. 5 m//s`B. ` 5 m//s`C. ` 3 m//s`D. ` 6 m//s`

Answer» Correct Answer - A::B::C
`a= (qE)/m = 0. 3 m//s^2 rArr at = 3 m//s^2`
` vec V = vec x + vec at`
From vector addition
`(x-at ) le V le u + a t`.


Discussion

No Comment Found

Related InterviewSolutions