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A particle `A` is projected from the ground with an initial velocity of `10m//s` at an angle of `60^(@)` with horizontal. From what height should an another particle `B` be projected horizontally with velocity `5m//s` so that both the particles collide in ground at point `C` if both are projected simultaneously `g=10 m//s^(2)`. A. `10 m`B. `15 m`C. `20 m`D. `30 m` |
Answer» Correct Answer - B `t=(2U sin theta)/g=sqrt3 , S=1/2"gt"^(2) h=15m` |
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