InterviewSolution
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InterviewSolution
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A particle A moves along a circle of radius `R=50cm` so that its radius vector r relative to the point O(figure) rotates with the constant angular velocity `omega=0.40rad//s`. Find the modulus of the velocity of the particle, and the modulus and direction of its total acceleration. A. `v=0.4 m//s, a=0.4 m//s^(2)`B. `v=0.32 m//s, a=0.32 m//s^(2)`C. `v=0.32 m//s, a=0.4 m//s^(2)`D. `v=0.4 m//s, a=0.32 m//s^(2)` |
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Answer» Correct Answer - D Angular velocity `omega` about centre `=2omega` `=2xx0.40=0.30 rad//sec` `v=omega R` `=0.80xx1/2=0.40 m//s` `a=v^(2)/R=(0.40xx0.40xx100)/50=0.32 cm//s^(2)` |
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