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A particle 'A' starts moving frorri point A with constant velocity 4 m/s along x-axis. Another particle 'B' initially at rest starts moving along x-axis after (8/3), sec after the start of A, with acceleration varying a=4=(3-t) m//s^(2) Total distance traveled by the particle B when it meets the particle A for the second time is : |
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Answer» `(304)/(3)m` |
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