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A particle 'A' starts moving frorri point A with constant velocity 4 m/s along x-axis. Another particle 'B' initially at rest starts moving along x-axis after (8/3), sec after the start of A, with acceleration varying a=4=(3-t) m//s^(2) The two particles will meet twice in the due course of their motion. The time interval between these two successive meets will be : |
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Answer» 6sec |
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