1.

A particle at rest starts moving in a horizontal straight line with uniform acceleration The ratio of the distance covered during the fourth and the third second is

Answer»

`(4)/(3)`
`(26)/(9)`
`(7)/(5)`
2

Solution :The distance travelled during NTH second `S_(N)u+(1)/(2)a(2n-1)`
Distance travelled during 4th second `S_(1)=(1)/(2)a(8-1)`
Distance travelled during 3rd second `S_(2)=(1)/(2)a(6-1)`
`:.(S_(1))/(S_(2))=(7)/(5)`


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