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A particle carrying charge + q is held at the center of a square of each side arranged on the square as shown in Fig. If q = 2 muC, what is the net force on the particle? |
Answer» As in clear from Fig. I(a)., forces on the particle at O due to `(-2 q, -2 q) , (-3 q, -3 q) and (+4 q, + 4 q)` are equal and opposite They cancel out in pairs. However, forces due to +7 q add up. There, net force on the particle at O is ` F = (1)/(4pi in_(o)) xx ((7q) (q) + 7q(q))/((1//2)^(2))` = `(9xx10^(9)xx14(2xx10^(-6))^(2))/(1//4)` ` = 36xx14xx4xx10^(-3) N` |
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