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A PARTICLE CROSSING THE ORIGIN OF CO ORDINATES AT TIME T=0 MOVES IN THE xy PLANE WITH A CONSTANT ACCELERATION a IN THE y -direction .IF ITS EQUATION OF MOTION ISyu= bx^2 THEN WHAT IS ITS ANGLE OF PROJECTION IN THE X DIRECTION ?

Answer» A PARTICLE CROSSING THE ORIGIN OF CO ORDINATES AT TIME T=0 MOVES IN THE xy PLANE WITH A CONSTANT ACCELERATION a IN THE y -direction .IF ITS EQUATION OF MOTION ISyu= bx^2 THEN WHAT IS ITS ANGLE OF PROJECTION IN THE X DIRECTION ?


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