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A particle executes S.H.M. of amplitude 25 cm and time period 3 s. What is the minimum time required for the particle to move between two points 12.5 cm on either side of the mean position ?A. 0.6 sB. 0.5 sC. 0.4 sD. 0.2 s

Answer» Correct Answer - B
`t=(T)/(12)+(T)/(12)=(T)/(6)`
`=(3)/(6)=(1)/(2)=0.5s`


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