InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A particle executes S.H.M with amplitude 0.2m and time period is 24s. The time required for it to move from the mean position to a point 0.1m isA) 2 sB) 3 sc) 8 sD) 12 s |
|
Answer» A) 2 s Explanations: Amplitude of particle executing SHM 0.2m. Time period T=24s Hence \(x=0.2sin\omega t\) \(sin\omega t=\frac{1}{2}=sin \frac{\pi}{6}\) \(\frac{2\pi}{24} t = \frac{\pi}{6}\) t= 2s |
|