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A particle executes SHM along x-axis with an amplitude A, time period T with origin as the mean position. At t = 0, if the particle starts in the +ve x-direction from the origin the minimum time in which it will be at `x=-A//2` will beA. `(T)/(12)`B. `(T)/(6)`C. `(T)/(4)`D. `(7T)/(12)` |
Answer» Correct Answer - D `-(A)/(2)=Asinomegat,sinomegat=-(1)/(2)impliesomegat=(7pi)/(6)` `t=(7T)/(12)`. |
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