A particle executes SHM of time period T. Find time by the particle to go from its mean position to half of the amplitude.

A particle executes SHM of time period T. Find time by the particle to

1.	A particle executes SHM of time period T. Find time by the particle to go from its mean position to half of the amplitude.
Answer» Solution :Consider the EQUATION of motion, X = `A sin wT ,` At t=0 , x=0 i.e. , at MEAN position The particle will be at x = `A/2` , at a time , where `A/2` = `A sin omega t = sin omega t = 1//2` , `sin omega t = sin pi//6` `omega t = pi/6 ` (or) `(2PI)/(T) t = (pi)/(6) `(or) `t= T/(12)` , Time taken `T/(12)`