A particle executes SHM of type x=Asinomegat. It takes time t_(1) from x=0 to x=(A)/(2) and t_(2) from x=(A)/(2) to x=A. The ratio t_(1):t_(2) will be

A particle executes SHM of type x=Asinomegat. It takes time t_(1) from

1.	A particle executes SHM of type x=Asinomegat. It takes time t_(1) from x=0 to x=(A)/(2) and t_(2) from x=(A)/(2) to x=A. The ratio t_(1):t_(2) will be
Answer» `1:1` `1:2` `1:3` `2:1` SOLUTION :`t_(1)+t_(2)=(T)/(4)` or `t_(2)=(T)/(4)-t_(1)` At time, `t=t_(1)x=(A)/(2)` `THEREFORE (A)/(2)=Asinomegat_(1)oromegat_(1)=(pi)/(6)ort_(1)=(pi)/(6omega)` `therefore t_(2)=(T)/(4)-(pi)/(6omega)=(2PI)/(4omega)-(pi)/(6omega)=(2pi)/(6omega) (because T=(2pi)/(omega))` `therefore t_(1):t_(2)=1:2`