A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find maximum velocity

A particle executes SHM represented by the equation , y= 0.02sin(3.14t

1.	A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find maximum velocity
Answer» Solution :COMPARING equation `y= 0.02sin(3.14t+ (PI)/(2))`with the general from of the equation , `y= A sin(omegat+phi_(0))` Maximum VELOCITY `v_("max")= AOMEGA= 0.02 xx 3.14= 0.68 ms^(-1)`