A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find time period

A particle executes SHM represented by the equation , y= 0.02sin(3.14t

1.	A particle executes SHM represented by the equation , y= 0.02sin(3.14t+ (pi)/(2)) meter. Find time period
Answer» Solution :comparing EQUATION `y= 0.02sin(3.14t+ (PI)/(2))`with the GENERAL from of the equation , `y= A SIN(omegat+phi_(0))` Time period (T ) is given by `T= (2pi)/(omega)` or `T= (2pi)/(3.14)= 2s`