A particle executes SHM such that, the maximum velocity during the oscillation is numerically equal to half the maximum acceleration. What is the time period?

A particle executes SHM such that, the maximum velocity during the osc

1.	A particle executes SHM such that, the maximum velocity during the oscillation is numerically equal to half the maximum acceleration. What is the time period?
Answer» Solution :GIVEN MAXIMUM velocity `V_("max") = 1/2 ` maximum acceleration `(a_("max"))` But `V_("max") = A OMEGA and a_("max") = omega^2`A `A omega = 1/2 . A omega^2 impliesomega = 2 `, Time period of the BODY `T= (2pi)/(omega) = (2pi)/(2) = pi` sec.