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A particle executes `SHM` with an amplitude of `10cm` and frequency `2 Hz`. At `t = 0`, the particle is at a point where potential energy and kinetic energy are same. The equation for its displacement isA. `x = 0.1 sin (4pi t+(pi)/(4))m`B. `x = 0.1 (sin 4pi t)m`C. `x = 0.1 cos(4pi t+(pi)/(3))`D. `x = 0.1(sin4pit-(pi)/(3))m` |
Answer» Correct Answer - A `x =A sin (omegat +phi), phi = (pi)/(4)` |
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