A particle executes simple harmonic motion of amplitude A. The distance from the mean position where its kinetic energy is equal to its potential energy, is

A particle executes simple harmonic motion of amplitude A. The distanc

1.	A particle executes simple harmonic motion of amplitude A. The distance from the mean position where its kinetic energy is equal to its potential energy, is
Answer» 0.81 A 0.71 A 0.61 A 0.51 A Solution :`1/2momega^(2)(A^(2)-X^(2))=1/2momega^(2)x^(2)or,A^(2)=2X^(2)` or, x = 0.71 A