A particle executes two types of SHM. x_(1) = A_(1) sin omega t " and "x_(2) =A_(2) sin [omega t+(pi)/(3)], then find the maximum acceleration of the particle.

A particle executes two types of SHM. x_(1) = A_(1) sin omega t " and

1.	A particle executes two types of SHM. x_(1) = A_(1) sin omega t " and "x_(2) =A_(2) sin [omega t+(pi)/(3)], then find the maximum acceleration of the particle.
Answer» Solution :MAXIMUM ACCELERATION `= -OMEGA^(2) x` `= -omega^(2) XX (sqrt(3)A_(2))/(2)`.