A particle executies linear simple harmonic motion with an amplitude `3cm` .When the particle is at `2cm` from the mean position , the magnitude of its velocity is equal to that of acceleration .The its time period in seconds isA. `(sqrt5)/(2 pi)`B. `(4 pi)/(sqrt(5)`C. `(2 pi)/(sqrt3)`D. `(sqrt5)/(pi)`

A particle executies linear simple harmonic motion with an amplitude `

1.	A particle executies linear simple harmonic motion with an amplitude `3cm` .When the particle is at `2cm` from the mean position , the magnitude of its velocity is equal to that of acceleration .The its time period in seconds isA. `(sqrt5)/(2 pi)`B. `(4 pi)/(sqrt(5)`C. `(2 pi)/(sqrt3)`D. `(sqrt5)/(pi)`
Answer» `v = omega sqrt((A^(2) - x^(2)))` `omega^(2) x = omega sqrt(A^(2) - x^(2))` `omega = (sqrt(A^(2) - x^(2)))/(x) = (sqrt((3)^(2) - (2)^(2)))/(2) = (sqrt(5))/(2)` `(2 pi)/(T) = (sqrt5)/(2)` `T = (4 pi)/(sqrt5)`

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