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    				| 1. | When a certain metallic surface is illuminated with monochromatic light of wavelength `lamda`, the stopping potential for photoelectric current is `3V_0` and when the same surface is illuminated with light of wavelength `2lamda`, the stopping potential is `V_0`. The threshold wavelength of this surface for photoelectrice effect isA. `4 lambda`B. `(lambda)/4`C. `(lambda)/6`D. `6 lambda` | 
| Answer» Correct Answer - A `(hc)/(lambda)=(hc)/(lambda_(0))+e. 3V_(0).....(i)` `(hc)/(2lambda)=(hc)/(lambda_(0))+e.V_(0)......(ii)xx3` `(i)-3(ii)` `(hc)/(lambda)-(3hc)/(2lambda)=(hc)/(lambda_(0))-(3hc)/(lambda_(0))` `-1/(2lambda)=-2/(lambda_(0)) implies lambda_(0)=4lambda` | |