A particle executing SHM, covers a displacement of half of amplitude in one second. Calculate its time period.

A particle executing SHM, covers a displacement of half of amplitude i

1.	A particle executing SHM, covers a displacement of half of amplitude in one second. Calculate its time period.
Answer» Solution :Displacement, `X = A sin(OMEGAT)` `X= (A)/(2)` `(A)/(2)= A sin(omegat)` `(1)/(2)= sin(omegat) , omegat= (pi)/(6)` `((2pi)/(T))t= (pi)/(6), t= (T)/(12)"sec"`