A particle executing SHM crossed points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3s. The time period is:

A particle executing SHM crossed points A and B with the same velocity

1.	A particle executing SHM crossed points A and B with the same velocity. Having taken 3 s in passing from A to B, it returns to B after another 3s. The time period is:
Answer» 15s 6s 12s 9s Solution :TIME PERIOD of oscillation= 2 x (A to B) + return to B) ` = 2 xx (3 + 3) , T = 12 s `