

InterviewSolution
Saved Bookmarks
1. |
A particle executing SHM has a maximum speed of `30 cm//s` and a maximum acceleration of `60 cm/s^(2)` . The period of oscillation isA. `pisec`B. `(pi)/(2)sec`C. `2pisec`D. `(pi)/(t)sec ` |
Answer» Let equation of an SHM is represented by `y=asinomegat` `v=(dy)/(dt)=aomegacosomegat` `rArr(v)max=aomega=30`" " .....(i)` Acceleration `(A)=(dx^(2))/(dt^(2))=-aomega^(2)sinomegat` `A_(max)=omega^(2)a=60" " .....(ii)` Eqs. (i) and (ii), we get `omega(omegaa)=60rArromega(30)=60` `rArromega=2rad//s` `rArr(2pi)/(T)=2red//srArrT=pisec` |
|